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Discussion Topic:
Over charging condition on '36 V8?
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Kens 36 |
04-24-2010 @ 6:01 AM
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Posts: 352
Joined: Oct 2009
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Sorry about the link - i had a comma at the end. The correct link is http://www.funprojects.com/index.cfm Ken
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lightflyer1 |
04-23-2010 @ 7:52 PM
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New Member
Posts: 107
Joined: Oct 2009
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Link doesn't work. I got mine at C&G I think. https://secure435.hostgator.com/~dlvry40/ufolder/ShowProducts.php?c=1&s=16&g=126&t=949
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Kens 36 |
04-22-2010 @ 4:42 PM
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Posts: 352
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Bob, Since Tom hasn't seen this yet, I'll chime in. The company that sells them is Fun Projects, Inc. in St. Charles, IL. Website: http://www.funprojects.com/index.cfm, phone 630-584-1471. Ken
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Flatbob |
04-22-2010 @ 3:50 PM
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TomO, I like that idea, where would I get one of these solid state units? Thanks, Bob
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TomO |
04-22-2010 @ 8:16 AM
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Senior
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Flatbob, It sounds like you have the 3rd brush set. I would now look into replacing the cutout with the solid state voltage regulator that looks like a cutout. It will keep your battery charged and not over charge it.
Tom
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supereal |
04-22-2010 @ 7:36 AM
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I'd run it there, as you are very close. Most old car dashboard ammeters don't move much, and are not reliable enough to set the charging rate. If we need to check system current, we use a clamp-on ammeter, as most VOM meters can't handle the load. That's why the voltmeter technique is helpful.
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Flatbob |
04-21-2010 @ 4:49 PM
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After brush adjustment my meter now shows slightly over 7 volts at fast idle & with headlights on amp. gauge shows zero charge.
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supereal |
04-21-2010 @ 10:06 AM
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Senior
Posts: 6819
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Yes, 8.5 volts is too high, and will cook your battery. Adjust the system voltage to no more than 7.5 volts at a fast idle. The purpose of the cutout is to disconnect the generator when the engine is shut down so the battery isn't drained. It isn't a voltage regulator of any kind with the three brush generator. We set those with a voltmeter, as most ammeters are not accurate enough to be reliable. Some high charging rates are due to a partially shorted battery, either sulfated or with a bad cell, causing a high resistance. A loose or otherwise batter cable can also raise system resistance. Voltage is the product of current multiplied by resistance.
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TomO |
04-21-2010 @ 7:57 AM
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Alan, My understanding of a cutout is that it is a common relay designed to close the points when 6.5 volts is applied to the coil. It will hold those points closed until the voltage drops below the pick voltage. It does not care about the state of charge of the battery, you need a voltage regulator to take the state of the battery charge into consideration.
Tom
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ford38v8 |
04-20-2010 @ 6:58 PM
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Senior
Posts: 2769
Joined: Oct 2009
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Flatbob, I believe Super and Tom will agree that 8.5V is too high, but also, that when you have a fully charged battery, your cutout should do its job and reduce the input down to 6.5V to 7V. This is also when you will see your ammeter show Zero+. After using the starter to fire up your engine, normally it will take 5-10 miles of normal driving to recharge the battery. A fast idle should do it in 15 minutes.
Alan
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